In this article on

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There are five shops A, B, C, D and E. They sell two different magazines - India Today and Outlook. The following given pie chart shows the total number of magazines sold by different shops in a particular month.

Then,

(16% of 800-x) / (22% of 800-x) = 2/3

As we all know,

So,

16% of 800 = (10% + 5% + 1%) of 800 = 80 + 40 + 8 = 128

Similarly,

22% of 800 = (20%+2%) of 800 = 160+16 = 176

Now the above formed equation can be written as,

=> (128-x) / (176-x) = 2/3

=> 384 - 3x = 352 - 2x

=> x = 32

So, the total number of Outlook magazines sold by both the shops B and C together will be = 32+32 = 64

Hence,

So Required Difference,

=> (58% - 42%) of 800

=> 16% of 800

=> (10% + 5% + 1%) of 800

=> 80+40+8

=> 128 [ANS]

Hence,

Here for simplicity we can write that,

25% more means,

=> 100% +25% = 125% = 125/100

And similarly 12.5% more means,

=> 100%+12.5% = 112.5% = 112.5/100

Now,

25% more magazines sold by shop C,

=> 22% of 800 × 125/100

=> (20%+2%) of 800 × 125/100

=> (160+16) × 125/100

=> 176 × 5/4

=> 220

12.5% more magazines sold by shop E,

=> 24% of 800 × 112.5/100

=> (20% + 4%) of 800 × 112.5/100

=> (160+32) × 112.5/100

=> 192 × 112.5/100

=> 216

So, Required Total number of magazines,

=> 220+216

=> 436 [ANS]

Hence,

=> 18% of 800

Now as we all know,

=> (10%+8%) of 800

=> 80 + (10%-2%) of 800

=> 80 + (80-16)

=> 80 + 64

=> 144

As given in the question, total number of magazines sold by A is equal to 36% of the total magazines purchased by shop A.

So from this we can understand that, the total number of unsold magazines of shop A will be (100%-36%) = 42% of total magazines purchased by shop A.

Therefore, it can be written as

36% -----------> 144

42% -----------> ?

After cross multiply,

=> ? = (144×42) / 36

=> ? = 256 [ANS]

Hence,

Magazines sold by shop C = 22% of 800

Magazines unsold by shop D = (100-20)% of 800

Required Ratio,

=> 22% of 800 : 80% of 800

=> 176 : 640

[Tip : 22% of 800 = (20% + 2%) of 800 = 160 + 16 = 176, similarly 80% of 800 = 800 - (20% of 800) = 800-160 = 640]

Do remember,

Now,

=> 176 : 640 can be written as,

=> 44 : 160, or

=> 11 : 40 [ANS]

Hence,

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**Data Interpretation Questions with Unique Solutions**we are sharing some solved questions based on Pie Chart. The questions from Dat Interpretation are usually asked in the quantitative aptitude section of all the competitive exams. Once understood the right approach to deal with such questions, this topic becomes easy to score more marks in very less time.
While attempting the questions from Data Interpretation, the candidates are required to first understand the data given carefully and then proceed towards answering the respective questions. We have tried our best to explain you the best possible tips and tricks to solve the complicated questions at a jiffy. Now, let us move towards solving the given problem.

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__DI Set - 4__

There are five shops A, B, C, D and E. They sell two different magazines - India Today and Outlook. The following given pie chart shows the total number of magazines sold by different shops in a particular month.

Q.1) If the total number of Outlook magazines sold by shop B and that by shop C are equal and the ration of India Today magazines sold by shop B to that sold by shop C is 2:3, then find the total number of Outlook magazines sold by B and C together.

(a) 80

(b) 32

(c) 64

(d) 96

(e) 108Q.1) If the total number of Outlook magazines sold by shop B and that by shop C are equal and the ration of India Today magazines sold by shop B to that sold by shop C is 2:3, then find the total number of Outlook magazines sold by B and C together.

(a) 80

(b) 32

(c) 64

(d) 96

(e) 108

__Solution__**Let the number of Outlook magazines sold by shop B be 'x'**

Then,

(16% of 800-x) / (22% of 800-x) = 2/3

As we all know,

100% of 800 ≈ 800

10% of 800 ≈ 80

1% of 800 ≈ 8

So,

16% of 800 = (10% + 5% + 1%) of 800 = 80 + 40 + 8 = 128

Similarly,

22% of 800 = (20%+2%) of 800 = 160+16 = 176

Now the above formed equation can be written as,

=> (128-x) / (176-x) = 2/3

=> 384 - 3x = 352 - 2x

=> x = 32

So, the total number of Outlook magazines sold by both the shops B and C together will be = 32+32 = 64

Hence,

**option (c) is the right answer**.**Q.2) If the total number of Outlook magazines sold by all the shops together is 58% of the total number of magazines sold by all the shops, then find the difference between number of India Today magazines sold by all the shops together and the number of Outlook magazines sold by all the shops together.**

(a) 85

(b) 132

(c) 144

(d) 154

(e) 128(a) 85

(b) 132

(c) 144

(d) 154

(e) 128

**: As given in the question that, total number of Outlook magazines sold by all the shops together is 58% of the total number of magazines sold by all the shops. Now this means that (100-58)% = 42% are India Today magazines.**__Solution__So Required Difference,

=> (58% - 42%) of 800

=> 16% of 800

=> (10% + 5% + 1%) of 800

=> 80+40+8

=> 128 [ANS]

Hence,

**Option (e) is the right answer.**

Q.3) If the total number of magazines sold by shop C is 25% more and that by E is 12.5% more in the next month, then what is the total number of magazines sold by shop C and E together in the next month ?

(a) 480

(b) 432

(c) 380

(d) 436

(e) 524Q.3) If the total number of magazines sold by shop C is 25% more and that by E is 12.5% more in the next month, then what is the total number of magazines sold by shop C and E together in the next month ?

(a) 480

(b) 432

(c) 380

(d) 436

(e) 524

__Solution :__Here for simplicity we can write that,

25% more means,

=> 100% +25% = 125% = 125/100

And similarly 12.5% more means,

=> 100%+12.5% = 112.5% = 112.5/100

Now,

25% more magazines sold by shop C,

=> 22% of 800 × 125/100

=> (20%+2%) of 800 × 125/100

=> (160+16) × 125/100

=> 176 × 5/4

=> 220

12.5% more magazines sold by shop E,

=> 24% of 800 × 112.5/100

=> (20% + 4%) of 800 × 112.5/100

=> (160+32) × 112.5/100

=> 192 × 112.5/100

=> 216

So, Required Total number of magazines,

=> 220+216

=> 436 [ANS]

Hence,

**Option (d) is the right answer**.**Q.4) The total number of magazines sold by A is equal to 36% of the total magazines purchased by shop A, then what is the total number of unsold magazines of shop A ?**

**(a) 276****(b) 216****(c) 356****(d) 256****(e) 208**__: Let us first calculate the total number of magazines sold by A,__**Solution**=> 18% of 800

Now as we all know,

100% of 800 ≈ 800

10% of 800 ≈ 80

1% of 800 ≈ 8

=> (10%+8%) of 800

=> 80 + (10%-2%) of 800

=> 80 + (80-16)

=> 80 + 64

=> 144

As given in the question, total number of magazines sold by A is equal to 36% of the total magazines purchased by shop A.

So from this we can understand that, the total number of unsold magazines of shop A will be (100%-36%) = 42% of total magazines purchased by shop A.

Therefore, it can be written as

36% -----------> 144

42% -----------> ?

After cross multiply,

=> ? = (144×42) / 36

=> ? = 256 [ANS]

Hence,

**Option (d) is the right answer.**

Q.5) Find the ratio of number of magazines sold by shop C to the number of magazines unsold by shop D.

(a) 11 : 40

(b) 17 : 60

(c) 16 : 27

(d) 9 : 16

(e) 11 : 20Q.5) Find the ratio of number of magazines sold by shop C to the number of magazines unsold by shop D.

(a) 11 : 40

(b) 17 : 60

(c) 16 : 27

(d) 9 : 16

(e) 11 : 20

__Solution__:Magazines sold by shop C = 22% of 800

Magazines unsold by shop D = (100-20)% of 800

Required Ratio,

=> 22% of 800 : 80% of 800

=> 176 : 640

[Tip : 22% of 800 = (20% + 2%) of 800 = 160 + 16 = 176, similarly 80% of 800 = 800 - (20% of 800) = 800-160 = 640]

Do remember,

100% of 800 ≈ 800

10% of 800 ≈ 80

1% of 800 ≈ 8

Now,

=> 176 : 640 can be written as,

=> 44 : 160, or

=> 11 : 40 [ANS]

Hence,

**Option (a) is the right answer**.**Note : Don't write these long sentences while solving the question in exam, they are written only to give you a proper explanation. Just cut short the steps by trying to understand the method or logic behind it and do most of the calculations in mind inorder to save the time.**That's all in this article, if you have any doubt, feedback or suggestion then please feel free to comment below. Keep Sharing and Happy Learning.

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